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ohaa [14]
4 years ago
8

IF the strong nuclear force affects all particles that are close to each other, What will happen if we add two neutrons to our n

ucleus with two protons?
A) It will decrease the electromagnetic force in the nucleus
B) It will decrease the strong nuclear force in the nucleus
C) It will increase the strong nuclear force in the nucleus
D) It will increase the electromagnetic force in the nucleus
Chemistry
2 answers:
Scorpion4ik [409]4 years ago
8 0

Answer : It will increase the strong nuclear force in the nucleus ( C )

Given that the strong nuclear force affects the particles that are close to each other addition of two neutrons and two protons, will cause an increase in the strong nuclear force found in the nucleus . this is because a Nucleus with two ( 2 ) protons exhibits attractive nuclear force and a repulsive coulomb force. and since the nuclear force does not depend on the charge, the addition of two neutrons the attractive nuclear force will increase

Hence we can conclude that addition of two neutrons to our nucleus with two protons will increase the strong nuclear force in the nucleus.

Learn more : brainly.com/question/22455703

Alina [70]4 years ago
7 0

Answer: it will increase the strong nuclear force in the nucleus

Explanation: Labster

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A gas mixture with a total pressure of 745 mmHg contains each of the following gases at the indicated partial pressures: CO2, 12
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Answer:

P_{He}=219mmHg

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Explanation:

Hello,

By applying the Dalton's law, we can compute the partial pressure of the helium has:

P_{tot}=P_{CO_2}+P_{Ar}+P_{O_2}+P_{He}

Now, solving for the partial pressure of the helium gas we get:

P_{He}=P_{tot}-P_{CO_2}-P_{Ar}-P_{O_2}=745mmHg-125mmHg-214mmHg-187mmHg\\P_{He}=219mmHg=0.288atm

On the other hand, the mass of the helium gas is computed via the ideal gas equation in terms of the helium's mass:

PV=\frac{m_{He}}{M_{He}}RT\\m_{He}=\frac{M_{He}PV}{RT} =\frac{4g/mol*0.288atm*12L}{0.082\frac{atm*L}{mol*K}*273K}\\ m_{He}=0.618gHe

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3 years ago
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Which of the following is true of gases?
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natural rubidium has the average mass of 85.4678 and is composed of isotopes 85 Rb(mass = 84.9117) and 87 Rb. The ratio of atoms
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Mass of Rb-87 is 86.913 amu.

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For 100% naturally occurring Rb = 2.591 + 1 = 3.591

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