Question

Consider a condenser in which steam at a specified temperature is condensed by rejecting heat to the cooling water. If the heat transfer rate in the condenser and the temperature rise of the cooling water is known, explain how the rate of condensation of the steam and the mass flow rate of the cooling water can be determined. Also, explain how the total thermal resistance R of this condenser can be evaluated in this case.

Answer 1

Answer:

Q = [ mCp ( ΔT) ] $_{cooling water }$

(ΔT)$_{cooling water}$ and  Q  is given

$m_{cooling water}$  = $\frac{Q}{Cp[ T_{out} - T_{in} ] }$

next the rate of condensation of the steam

Q = [ m$h_{fg}$ ]$_{steam}$

  $m_{steam} = \frac{Q}{h_{fg} }$

Total resistance of the condenser is

R = $\frac{Q}{change in T_{cooling water } }$

Explanation:

How will the rate of condensation of the steam and the mass flow rate of the cooling water can be determined

Q = [ mCp ( ΔT) ] $_{cooling water }$

(ΔT)$_{cooling water}$ and  Q  is given

$m_{cooling water}$  = $\frac{Q}{Cp[ T_{out} - T_{in} ] }$

next the rate of condensation of the steam

Q = [ m$h_{fg}$ ]$_{steam}$

  $m_{steam} = \frac{Q}{h_{fg} }$

Total resistance of the condenser is

R = $\frac{Q}{change in T_{cooling water } }$