Since the car is at rest, the force experienced by car will be normal face(exerted by surface to which car is in contact) and weight of the car.
As the car is at rest, net force on the car should be zero.
Answer:
The impala pushed down the ground with a force of 37.49N
Explanation:
The force at which the impala pushed down the ground can be calculated for using the Newton's second law of motion,
Force = mass × acceleration
Force = mass ×(velocity/time)
Given mass = 25.5kg
Time = 0.21seconds
To get the velocity, we will use one of the equation of motions;
Using v² = u²+2gH
where;
H is the height reached from the ground = 2.5m
g = 9.81m/s²
u is the initial velocity = 0m/s
v is the final velocity=?
Substituting this values to get the final velocity v;
v² = 0²+2(9.81)(2.5)
v² = 49.05
v = √49.05
v = 7.0m/s
Substituting this velocity into the formula for force we have;
Force = 25.5×(7.0/0.21)
Force = 25.5 × 1.47
Force = 37.49N
The impala pushed down the ground with a force of 37.49N
car starts from rest
final speed attained by the car is
acceleration of the car will be
now the time to reach this final speed will be
so it required 1.39 s to reach this final speed
Answer:
kg
Explanation:
the highr and jebad to kilogram mizans