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Oxana [17]
3 years ago
5

In order to ride a bike up a hill with increasing speed—

Physics
2 answers:
zaharov [31]3 years ago
6 0

Answer:

the riders must be greater than friction and the force of gravity. uh I guessed

polet [3.4K]3 years ago
3 0
The correct answer would be: “the riders pedal force must be greater than friction and the force of gravity”

hope this helps!
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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
Arada [10]

Answer:D

Explanation: both variables change in the same direction. An increase in one variable leads to an increase in the other, a decrease in one lead to a decrease the another

5 0
4 years ago
Look at the diagram below. The value of equivalent resistor is: A. 4 Ω B. 6 Ω C. 8 Ω D. 10 Ω
Advocard [28]

Answer:

R=4Ω

Explanation:

R1 and R3 are parrallel

so we have : R=R1*R2/R1+R2

R=6*3/6+3

R=18/9

R=2Ω

R2 and 2Ω are in series,so we have

R=R2+2

R=2+2

R=4Ω

5 0
3 years ago
Tabitha hit a 0.25 kg volleyball straight up into the air with 45 Joules of energy. How high did volleyball soar up? Round to th
zavuch27 [327]

Answer:

18 m

Explanation:

E = mgh

45 J = (0.25 kg) (9.8 m/s²) h

h = 18 m

7 0
4 years ago
A snowboarder starts from rest on an inclined planar snow surface and gives herself a tiny push to start sliding down the hill.
tiny-mole [99]

Answer:

v = 26.52 m/s

Explanation:

Here we know that as she passes the flag she will gain some speed

so here we can say that

Work done by all forces = change in kinetic energy of the system

so we will have

W_g + W_f = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

here we know that

W_g = mgh

W_f = -\mu mg d

v_i = 0

h = 39.78 m

d = 27.81 m

so we have

mgh - \mu mg d = \frac{1}{2}mv^2 - 0

(9.8)(39.78 - (0.14)(27.81)) = \frac{1}{2} v^2

v = 26.52 m/s

8 0
3 years ago
an object with a mass of 1.5 kg changes its velocity from 15 m/s to 22 m/s during a time interval of 3.5 seconds. what impulse w
natulia [17]
Impulse is the change in momentum

J = 1.5 kg(22 m/s - 15 m/s) = 10.5 kg-m/s
6 0
3 years ago
Read 2 more answers
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