Water is flowing steadily through a 3-m long, 20 mm innerdiameter cast iron pipe. The water enters at a uniform velocity U and e
1 answer:
Answer:
Hello your question is incomplete attached below is the complete question
answer :
U/r = R = [ 1 -
] = 0
∴ No slip condition is satisfied
Explanation:
Given that
Outlet velocity U(r) = [ 1 -
]
<u>prove that the output velocity profile satisfies the no slip condition</u>
at no slip u = 0 ( i.e. at the pipe's inner surface )
at , r = R ( inference is at center )
hence U/r = R = [ 1 -
] = 0
∴ No slip condition is satisfied
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Answer:
(a) attached below
(b)
(c)
(d) Ω
(e) and
Explanation:
Given data:
(a) Draw the power triangle for each load and for the combined load.
°
°
≅
≅
The negative sign means that the load 2 is providing reactive power rather than consuming
Then the combined load will be
(b) Determine the power factor of the combined load and state whether lagging or leading.
or in the polar form
°
The relationship between Apparent power S and Current I is
Since there is conjugate of current I therefore, the angle will become negative and hence power factor will be lagging.
(c) Determine the magnitude of the line current from the source.
Current of the combined load can be found by
(d) Δ-connected capacitors are now installed in parallel with the combined load. What value of capacitive reactance is needed in each leg of the A to make the source power factor unity?Give your answer in Ω
Ω
(e) Compute the magnitude of the current in each capacitor and the line current from the source.
Current flowing in the capacitor is
Line current flowing from the source is
Answer:
Check the explanation
Explanation:
Points to consider:
We need to take the input from the user
We need to find the manhatan distance and euclidian using the formula
(x1, y1) and (x2, y2) are the two points
Manhattan:
Euclidian Distance:
Code
#include<stdio.h>
#include<math.h>
struct Point{
int x, y;
};
int manhattan(Point A, Point B){
return abs(A.x - B.x) + abs(A.y- B.y);
}
float euclidean(Point A, Point B){
return sqrt(pow(A.x - B.x, 2) + pow(A.y - B.y, 2));
}
int main(){
struct Point A, B;
printf("Enter x and Y for first point: ");
int x, y;
scanf("%d%d", &x, &y);
A.x = x;
A.y = y;
printf("Enter x and Y for second point: ");
scanf("%d%d", &x, &y);
B.x = x;
B.y = y;
printf("Manhattan Distance: %d\n", manhattan(A, B));
printf("Euclidian Distance: %f\n", euclidean(A, B));
}
Sample output
Answer:
attached below
Explanation:
