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STALIN [3.7K]
3 years ago
12

1.A student pushes a 20.0 kg mass 10.0 m across a floor with a horizontal force of 80.0 N. Calculate the amount of work that the

student docs.
Work = Force x Distance

W = F x d
Physics
1 answer:
Alina [70]3 years ago
7 0
W = (10.0 m)(80.0 N)
W = 800 J
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An airplane travels 2400 km at a speed of 600 km/h, decreases its speed to 400 km/h for the next 1200 km and travels the last 2,
Alexus [3.1K]
Forget the numbers and think about how speed works for a second. If a plane flies at 600km/h, this means that it will fly exactly 600 km in 1 hour. So, how long would it take to fly 2400 km??

2400/600 = 4hours.

Do this for all three and add up the hours.

Total time: 12 hours

Average speed is the total distance / total time.

So,

Add up all the distances and divide by 12.

(2400+1200+2500) / 12

Average speed: 508.33333333 km/h
7 0
3 years ago
A 65 kg cart travels at a constant speed of 4.6 m/s. What is its kinetic energy?
Talja [164]

Answer:

Explanation:

mass (m) = 65 kg

velocity (v) = 4.6 m/s

Kinetic energy (KE)

= 1/2 * m * v²

= 1/2 * 65 * 4.6²

=  687.7 J

hope it helps :)

7 0
3 years ago
A student performs an experiment in measuring the period of a simple pendulum of known length 49.0 cm.He performed five trials a
Levart [38]
Correct Answer is Bb
4 0
3 years ago
You hang different masses M from the lower end of a vertical spring and measure the period T for each value of M. You use Excel
Svetradugi [14.3K]

Answer:

a)693.821N/m

b)17.5g

Explanation:

We the Period T we can find the constant k,

That is

T = 2 \pi \sqrt{\frac{m}{k}}

squaring on both sides,

T^2=\frac{4\pi^2}{k}M +\frac{4\pi^2}{k}m_{spring}

where,

M=hanging mass, m = spring mass,

k =spring constant

T =time period

a) So for the equation we can compare, that is,

y=T^2=0.0569x+0.0010

the hanging mass M is x here, so comparing the equation we know that

\frac{4\pi^2}{k}=0.0569\\k= \frac{4\pi^2}{0.0569}\\k=693.821N/m

b) In order to find the mass of the spring we make similar process, so comparing,

\frac{4\pi^2}{k}m =0.001\\m=\frac{0.004k}{4\pi^2} =\frac{0.001*693.821}{4\pi^2}\\m=0.0175kg\\m=17.5g

3 0
3 years ago
A block is placed on an inclined plane and remains stationary, as shown in the figure above. A student claims, “The block remain
Nina [5.8K]

Answer:

No, according to Newton's first law of motion, the block cannot exert a force on itself, and the body will remain at rest unless unbalanced forces act on it

However according to Newton's third and first laws of motion the action of gravity pulling the block down the plane is equal to the reaction force of friction, preventing the motion

Explanation:

According to Newton's third law, the action force of gravity on the block tending to drag the block down along the inclined plane is equal to the reaction force of the frictional force of the inclined plane due to the interactions between the surfaces of the block and the plane which tends to prevent the motion of the block when both the component of the gravitational force down the plane and the frictional force are equal.

4 0
3 years ago
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