Explanation:
Given that,
Length of each rod, L = 15 m
Area of cross section of the rod,
Young's modulus for steel,
Total weight of two people, F = 1900 N
We need to find the stretching in the rod when the ride is at rest. The formula of Young's modulus of a material is given by :
Here, is the stretching in the rod
So, the rod will stretched to
when car moves along a circular path then centripetal force for taking turn will be provided by the component of normal force
Let the road is tilted by some angle
so force equations are given as
now divide two equations
now as it is given to us that
now we have
so it is inclined at an angle of 45 degree
Answer:
MOMENTUM of the football player before collision is 110×8 =880
Explanation:
Answer:
The time is 176 seconds
Explanation:
We use the formula:
V= d/t V=velocity, d= distance, t= time
259 m/s= 45683 m/ t
t= 45683 m// 259 m/s
t= 176, 3 seg
<h3>
Answer: Approximately 4.67 m/s^2</h3>
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Explanation:
Let's say you want to push the brick to the right. The free body diagram will have an arrow pointing right on the rectangle (the brick) and the arrow is labeled with 35 N.
Friction always counteracts whatever force you apply. The friction force arrow will point left and be labeled with 7 N.
The net horizontal force is therefore 35-7 = 28 N and the direction is to the right. The positive net force means you've overcome the force of friction and the brick is moving.
F = 28 is the net force
m = 6 is the mass
a = unknown acceleration
F = m*a .... newton's second law
28 = 6a
6a = 28
a = 28/6
a = 4.67
The acceleration of the brick is approximately 4.67 m/s^2
This means that for every second, the brick's velocity is increasing by about 4.67 m/s.