Which of these statements about water is true?
2 answers:
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Answer:
Here's what I get
Explanation:
The ionization energy (I) is the energy required to remove an electron from an atom in the gaseous phase.
You can remove electrons in succession and measure the energies required as I₁, I₂, I₃, etc.
Thus, the removal of two electrons from Cu gives you Cu²⁺.
I found the ionization energies of Cu and used them to create those of Cu²⁺ (see table and graph below).
The electron configuration of Cu²⁺ is
Cu²⁺: 1s² 2s²2p⁶ 3s²3p⁶ 3d⁹
You can remove the nine 3d electrons and then there is a sudden jump from I₉ to I₁₀ as you break into the filled [Ar] configuration.
Similarly, there is big jump from I₁₇ to I₁₈ as you break into the filled [Ne] configuration.
The given elements put into an equation using their symbols are as follows:
Pb +
= 
+ Ag
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + = + Ag
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +
= + Ag
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + = + 2Ag
That is your final equation
The coefficients are 2 + 2 = 1 + 2
Pb +
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb +
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb +
That is your final equation
The coefficients are 2 + 2 = 1 + 2