Question

An ideal step-down transformer has a turns ratio of 1/106. An ac voltage of amplitude 170 V is applied to the primary. If the primary current amplitude is 8.10 mA, what is the secondary current amplitude

Answer 1

Answer:

$I_2=0.8586A$

Explanation:

From the question we are told that:

Turns Ratio i.e$\frac{N_2}{N_1}=\frac{1}{106} (step down)$

Voltage $v=170v$

Primary current amplitude$I_1= 8.10 mA =>8.10*10^{-3}A$

Generally the equation for a Transformer is mathematically given by

$\frac{E_1}{E_2}=\frac{I_2}{I_1}=\frac{N_1}{N_2}$

Therefore

$I_2=\frac{N_1}{N_2}*I_1$

$I_2=106*8.10*10^{-3}$

$I_2=0.8586A$