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pogonyaev
3 years ago
6

PLEASE HELP I WILL GIVE BRAINLIEST IF RIGHT!!!!

Physics
2 answers:
marta [7]3 years ago
6 0

Answer:

The answer is D

Hope this helped

PLEASE GIVE BRAINLIEST

Explanation:

NemiM [27]3 years ago
5 0
The answer is d, because it’s the tallest on the coaster.
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If a wave has amplitude of 0.2 meters, a wavelength of 0.5 meters, and a frequency of 32 Hz, at what speed is it moving?
GarryVolchara [31]
The velocity, frequency and wavelength of a wave are related by:
v = fλ
v = 32 x 0.5
v = 16 m/s
The answer is B.
3 0
3 years ago
What is the largest volcano in the solar system
Alchen [17]

Answer:

Olympus Mons on Mars.

Explanation:

It was discovered on Mars in 1971 and stands at a monstrous 21.9 km.

For reference, Mount Everest stands at 8.8K.

8 0
3 years ago
12*3a car is stopped at a traffic light. it then travels along a straight road so that its distance from the light is given by w
Digiron [165]
Missing parts in the text of the exercise:
- The distance from the traffic light is given by x(t) = bt^2 -ct^3, where b=2.4 m/s^2 and c=0.13 m/s^3

Solution:

part a) <span>calculate the average velocity of the car for the time interval t=0 to t=8.0 s
- The average velocity is given by the ratio between the distance covered in the time interval:
</span>v_{ave} =  \frac{x(8.0 s)-x(0 s)}{8.0 s-0 s}
x(0 s), the distance covered after t=0 s, is zero, while the distance after t=8.0 s is
x(8.0 s)=b(8 s)^2-c(8 s)^3 = (2.4 m/s^2)(8 s)^2 -(0.13 m/s^3)(8 s)^3=
=87.04 m
Therefore, the average velocity is
v_{ave}= \frac{x(8.0 s)-x(0)}{8.0s-0}= \frac{87.04 m}{8.0s}= 10.88 m/s

part b) <span>calculate the instantaneous velocity of the car at t=0, t=4.0 s and t=8.0 s
- The instantaneous velocity can be found by performing the derivation of x(t):
</span>v(t) = \frac{dx(t)}{dt}=2bt-3ct^2
<span>So now we just have to substitute t=0, t=4 s and t=8 s:
- t=0: v(0)=0
- t=4 s: </span>v(4.0 s)=2(2.4 m/s^2)(4.0 s)-3(0.13 m/s^2)(4.0s)^2=12.96 m/s
- t=8 s: v(8.0 s)=2(2.4 m/s^2)(8.0 s)-3(0.13 m/s^2)(8.0s)^2=13.44 m/s

part c) <span>how long after starting from rest is the car again at rest?
- To solve this part we must find the value of t for which v(t)=0, so:
</span>2bt-3ct^2=0
t(2b-3ct)=0
<span>The first solution is t=0 s, which corresponds to the beginning of the motion, so we are not interested in this value. The second solution is
</span>t= \frac{2b}{3c}= \frac{2\cdot 2.4 m/s^2}{3 \cdot 0.13 m/s^3}=12.31 s
<span>and this is the time at which the car is at rest again.</span>
8 0
4 years ago
How does increasing the amount of charge on an object affect the electric force it exerts on another charged object?
Ostrovityanka [42]

Answer: The electric force increases because the amount of charge has a direct relationship to the force.

Explanation:

5 0
3 years ago
Use vectors to decide whether the triangle with vertices P(1, −2, −1), Q(2, 1, −3), and R(6, −1, −4) is right-angled. Yes, it is
Andreas93 [3]

Answer:

Yes, it is right-angled

Explanation:

Two vectors are orthogonal if the scalar product between them is zero. Then, we will match each pair of vertices with a vector, wich is formed with the following formula:

Given two points A and B, the vector going from A to B is

AB=B-A=(B_{x}-A_{x},B_{y}-A_{y},B_{z} -A_{z})

So, we calculate each component separately.

PQ=Q-P=(2-1,1-(-2),-3-(-1))=(1,3,-2)

QR=R-Q=(6-2,-1-1,-4-(-3))=(4,-2,-1)

RP=P-R=(1-6,-2-(-1),-1-(-4))=(-5,-1,3)

Finally, using the scalar product formula

A*B=A_{x}* B_{x}+ A_{y}* B_{y}+ A_{z}* B_{z}

we see if the products is zero

PQ*QR=1*4+3(-2)+(-2)*(-1)=0

In this case we don't even have to calculate the other products as we've found that PQ and QR form a right angle.

3 0
3 years ago
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