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2 years ago

A school bus moves at speed of 35mi/he for 20miles. How long will it take for the bus to get to school

Physics

1 answer:

lara [203]2 years ago

8 0

Answer:

Time, t = 0.57 hours

Explanation:

It is given that,

Speed of the school bus, v = 35 mi/hr

Distance covered by the bus, d = 20 miles

We need to find the time taken by the bus to get to school. Time taken by the bus is given by :

t = 0.57 hours

So, the time taken by the bus to reach school is 0.57 hours. Hence, this is the required solution.

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Read each scenario and then answer the question scenario a 120 J of work is done in 6 seconds Scenario b 160 J of work is done i

Zielflug [23.3K]

Answer:

all scenarios are using the same power

Explanation:

we know that power is defined as P(Watts)=W(Joules)/t(seconds).

When applying this formula to each of the scenarios we find:

$\frac{120J}{6s}=\frac{160J}{8s}=\frac{200J}{10s}= 20W$

Done

7 0

2 years ago

A motorcycle, which has an initial linear speed of 8.0 m/s, decelerates to a speed of 2.2 m/s in 4.1 s. Each wheel has a radius

SVETLANKA909090 [29]

Answer:

Explanation:

Given

Initial linear speed $v_1=8 m/s$

initial angular velocity $\omega _1=\frac{v_1}{r}=\frac{8}{0.6}=13.33 rad/s$

Speed after 4.1 s is $v_2=2.2 m/s$

$\omega _2=\frac{2.2}{0.6}=3.66 rad/s$

using $\omega _2=\omega _1+\alpha t$

where $\alpha$ is angular acceleration

$3.66=13.33+\alpha \cdot 4.1$

$\alpha =-2.37 rad/s^2$ i.e. clockwise

(b)angular displacement

$\theta =\omega _1t+\frac{\alpha t^2}{2}$

$\theta =13.33\times 4.1-\frac{2.37\cdot 4.1^2}{2}$

$\theta =54.66-19.75$

$\theta =34.91 rad$

3 0

3 years ago

4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.

mixer [17]

Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)

(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS

Explanation:

SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.

FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.

3 0

1 year ago

A 500 kg empty elevator moves with a downwards acceleration of 2 m/s2. What is the tension force of the cable on the elevator? 5

Gre4nikov [31]

Answer:

T = 4000 N

Explanation:

We have,

Mass of an elevator, m = 500 kg

It is moving downward with an acceleration of $2\ m/s^2$ . It is required to find the tension force of the cable on the elevator. We know that when the elevator is moving downward, the net force on it is given by :

$F=m(g-a)$

g is acceleration due to gravity

$F=500\times (10-2)\\\\F=4000\ N$

So, the tension force of the cable on the elevator is 4000 N.

5 0

3 years ago

Which are characteristics of a gas? (Select all that apply.)It cannot move.It fills the container it is in.It can be compressed.

Aleonysh [2.5K]

Answer: no definite shape (takes the shape of its container)

no definite volume.

particles move in random motion with little or no attraction to each other.

highly compressible.

Explanation:

Gases have three characteristic properties: (1) they are easy to compress, (2) they expand to fill their containers, and (3) they occupy far more space than the liquids or solids from which they form.

4 0

2 years ago