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anastassius [24]

3 years ago

5

Tell me how the temperatures in the tropics, temperate zones, and polar zones are similar and how they are different.

1 answer:

Oksi-84 [34.3K]3 years ago

6 0

Answer:

Hewo My Lovelys!!

Answers are down below!!

Explanation:

The climate region near the equator with warm air masses is known as tropical. In tropical and polar climates, the weather is consistent throughout the year. In temperate zones, the weather is affected by both warm and cold air masses at different times during the year, so the weather changes with the seasons.

Hope this helps!! =3

Have a great day, evening, or night!! <3

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iragen [17]

I believe it’s 60km/h

I divided the total distance (120 km) by the time it took to get there (2h) to get this.

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3 years ago

A blue box and green box are sitting on a table not moving. A student exerts the same force on both boxes and observes how long

dem82 [27]

Answer:

2 possible answers. 1. The green box is heavier. or 2nd. The green box has bigger friction than blue box.

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3 years ago

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If a force of 50 Newton’s was applied to an object with a mass of 500 grams, what will the objects acceleration be?

lapo4ka [179]

Answer: 100 m/s^2

F=ma

Explanation:

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3 years ago

Describe the difference between distance, position, and displacement

nata0808 [166]

Answer:

Explanation:

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5 0

3 years ago

A volcano erupts and launches a chunk of hot magma horizontally with a speed of 252 m/s. The magma travels a horizontal distance

ArbitrLikvidat [17]

Answer:

The value is $v_y = -48.61 \ m/s$

Explanation:

From the question we are told that

The horizontal speed is $u_x = 252 \ m/s$

The horizontal distance is $d = 1250 \ m$

Generally the time taken by the hot magma in air before landing is mathematically represented as

$t = \frac{d}{u_x}$

=> $t = \frac{ 1250 }{252}$

=> $t = 4.96 \ s$

Generally the initial vertical velocity of the magma when it was lunched is

$u_y = 0 \ m/ s$

Then the final velocity of the magma when it hits the ground is mathematically represented s

$- v_y = u_y + gt$

Here the negative sign mean that the direction of the velocity is towards the negative y -axis

So

$- v_y = 48.61 \ m/s$

=> $v_y = -48.61 \ m/s$

7 0

3 years ago