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2 years ago

Tell me how the temperatures in the tropics, temperate zones, and polar zones are similar and how they are different.

Physics

1 answer:

Oksi-84 [34.3K]2 years ago

6 0

Answer:

Hewo My Lovelys!!

Answers are down below!!

Explanation:

The climate region near the equator with warm air masses is known as tropical. In tropical and polar climates, the weather is consistent throughout the year. In temperate zones, the weather is affected by both warm and cold air masses at different times during the year, so the weather changes with the seasons.

Hope this helps!! =3

Have a great day, evening, or night!! <3

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When heat is converted into another form of energy, the total amount of energy is constant. Which law best illustrates this stat

Lorico [155]

The correct option is (A) the first law of thermodynamics

Explanation:
The first law of thermodynamics takes the idea of law of conservation of energy and modify it for thermodynamics systems. It is the total internal energy of the systems equals to the amount of heat added "to" the system and the workdone "by" the system given as:
ΔU = Q - W
Q = heat added TO the system
W = work BY the system
ΔU = Total internal energy

But the total internal energy is CONSERVED; it means that energy cannot be created or destroyed; it can only be transformed from one form to another. Hence the correct option is (A).

6 0

3 years ago

Read 2 more answers

Momentum is a measure of the of an object. Which term accurately completes the sentence?

RideAnS [48]

Answer:

Momentum is define as the product of the mass and velocity of a body. It is measured in Kgm/s.

Explanation:

Momentum is the product of mass and velocity of an object. When an object or a body of mass 'm' is moving with velocity 'v', then its momentum can be determined as;

momentum (P) = mass × velocity

i.e P = m × v

= mv

It is measured in Kgm/s.

The change in momentum of a body is referred to as its impulse (Ft).

ΔP = m(v - u) = Ft

Where: P is the momentum of the object, m is its mass, v is its final velocity, u is the initial velocity, F is the force and t is the time in which the force acts.

8 0

3 years ago

Read 2 more answers

If the mass of the ladder is 12.0 kgkg, the mass of the painter is 55.0 kgkg, and the ladder begins to slip at its base when her

Marysya12 [62]

Answer:

μ = 0.336

Explanation:

We will work on this exercise with the expressions of transactional and rotational equilibrium.

Let's start with rotational balance, for this we set a reference system at the top of the ladder, where it touches the wall and we will assign as positive the anti-clockwise direction of rotation

fr L sin θ - W L / 2 cos θ - W_painter 0.3 L cos θ = 0

fr sin θ - cos θ (W / 2 + 0,3 W_painter) = 0

fr = cotan θ (W / 2 + 0,3 W_painter)

Now let's write the equilibrium translation equation

X axis

F1 - fr = 0

F1 = fr

the friction force has the expression

fr = μ N

Y Axis

N - W - W_painter = 0

N = W + W_painter

we substitute

fr = μ (W + W_painter)

we substitute in the endowment equilibrium equation

μ (W + W_painter) = cotan θ (W / 2 + 0,3 W_painter)

μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)

we substitute the values they give

μ = cotan θ (12/2 + 0.3 55) / (12 + 55)

μ = cotan θ (22.5 / 67)

μ = cotan tea (0.336)

To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45

cotan 45 = 1 / tan 45 = 1

the result is

μ = 0.336

5 0

3 years ago

A bike first accelerates from 0.0m/s to 4.5m/s in 4.5 s, the continues at this constant speed for another 6.0 s. What is the tot

Alex_Xolod [135]

Answer:

37.125 m

Explanation:

Using the equation of motion

s=ut+0.5at^{2} where s is distance, u is initial velocity, t is time and a is acceleration

Distance during acceleration

Acceleration, a=\frac {V_{final}-V_{initial}}{t} where V_{final} is final velocity and V_{initial} is initial velocity.

Substituting 0.0 m/s for initial velocity and 4.5 m/s for final velocity, acceleration will be

a=\frac {4.5 m/s-0 m/s}{4.5 s}=1 m/s^{2}

Then substituting u for 0 m/s, t for 4.5 s and a for 1 m/s^{2} into the equation of motion

s=0*4.5+ 0.5*1*4.5^{2}=0+10.125 =10.125 m

Distance at a constant speed

At a constant speed, there's no acceleration and since speed=distance/time then distance is speed*time

Distance=4.5 m/s*6 s=27 m

Total distance

Total=27+10.125=37.125 m

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3 years ago

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lawyer [7]

Answer:

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