Answer:
(a) 62460 kg/hr
(b) 17,572.95 kW
(c) 3,814.57 kW
Explanation:
Volumetric flow rate, G = 30 m³ / 1 min => 90 / 60 => 1.5
Calculate for h₁ , h₂ , h₃
h₁ is h at P = 40 bar, 500°C => 3445.84 KJ/Kg
Specific volume steam, ц = 0.086441 m³kg⁻¹
h₂ is h at P = 20 bar, 400°C => 3248.23 KJ/Kg
h₃ is h at P = 20 bar, 500°C => 3468.09 KJ/Kg
h₄ is hg at P = 0.6 bar from saturated water table => 2652.85 KJ/Kg
a)
Mass flow rate of the steam, m = G / ц
m = 1.5 / 0.086441
m = 17.35 kg/s
mass per hour is m = 62460 kg/hr
b)
Total Power produced by two stages
= m (h₁ - h₂) + m (h₃ - h₁)
= m [(3445.84 - 3248.23) + (3468.09 - 2652.85)]
= m [ 197.61 + 815.24 ]
= 17.35 [1012.85]
= 17,572.95 kW
c)
Rate of heat transfer to the steam through reheater
= m (h₃ - h₂)
= 17.35 x (3468.09 - 3248.23)
= 17.35 x 219.86
= 3,814.57 kW
