what is it ill know your question??!!
Answer:
44197.55 N
Explanation:
From the question,
Pressure of the pressure guage (P) = Total force experienced by the cover (F)/Area of the cover (A)
P = F/A................ Equation 1
make F the subeject of the equation
F = P×A............... Equation 2
Given: P = 552 psi = (552×6894.76) = 3805907.52 N/m², A = 18 square inches = (18×0.00064516) = 0.01161288 m²
Substitute these values into equation 2
F = ( 3805907.52×0.01161288)
F = 44197.55 N
Answer:
- import java.util.Scanner;
- import java.util.Random;
- public class Main {
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
- Random rand = new Random();
-
- System.out.print("Enter number of questions you wish to practice: ");
- int n = input.nextInt();
-
- int i = 1;
- while(i <= n){
- int num1 = 1 + rand.nextInt(10);
- int num2 = 1 + rand.nextInt(10);
- int answer = num1 * num2;
- System.out.print("Question " + i + ": " + num1 + " x " + num2 + " = ");
- int response = input.nextInt();
-
- if(response == answer){
- System.out.println("Correct answer!");
- }
- else{
- System.out.println("Wrong answer. It should be " + answer);
- }
- i++;
- }
- }
- }
Explanation:
Firstly, we import Scanner and Random classes (Line 1-2) as we need to get user input for number of questions and generate random number in each question.
Next, create a Scanner and Random object (Line 7-8). Prompt user to input number of question and get the input using the Scanner object (Line 10-11).
Next create a while loop and set the condition to loop for n number of times (based on number of questions) (Line 14). In the loop, use Random object nextInt method to generate two integers between 1 -10 (Line 15-16). Prompt user to input an answer using the Scanner object (Line 18-19). If the response is matched with answer print a correct message (Line 21-22) other wise inform user they write a wrong answer and show the correct answer (Line 24-25).
Answer:
Part 1: It would be a straight line, current will be directly proportional to the voltage.
Part 2: The current would taper off and will have negligible increase after the voltage reaches a certain value. Graph attached.
Explanation:
For the first part, voltage and current have a linear relationship as dictated by the Ohm's law.
V=I*R
where V is the voltage, I is the current, and R is the resistance. As the Voltage increase, current is bound to increase too, given that the resistance remains constant.
In the second part, resistance is not constant. As an element heats up, it consumes more current because the free sea of electrons inside are moving more rapidly, disrupting the flow of charge. So, as the voltage increase, the current does increase, but so does the resistance. Leaving less room for the current to increase. This rise in temperature is shown in the graph attached, as current tapers.
