Answer:
A hypothesis states your predictions about what your research will find. It is a tentative answer to your research question that has not yet been tested. For some research projects, you might have to write several hypotheses that address different aspects of your research question
Explanation:
Answer:
The new position is 0.1865 m
Explanation:
As the context of the data is not available, thus following data is utilized from the question as attached above
x_relax=0.32 m
x_stiff=0.13 m
spring stiffness k=9 N/m
mass of block =0.073 kg
t=0.07 s
Velocity of the block is to be estimated thus
Force due to compression in spring is given as
F_s=k Δx
F_s=9(0.32-0.13)
F_s=1.71 N
Force on the block is given as
F_m=mg
F_m=0.073 x 9.8
F_m=0.71 N
Net Force
F=F_s-F_m
F=1.71-0.71 N
F=1 N
As Ft=Δp
So
Δp=1x0.07=0.07 kgm/s
Δp=p_final-p_initial
0.07=p_final-0
p_final=0.07 kgm/s
p_final=m*v_f
v_f=(p_final)/(m)
v_f=0.07/0.073
v_f=0.95 m/s
So now the velocity of the block is 0.95 m/s
time is 0.07 s
y_new=y_initial+y_travel
y_new=0.12+(0.95 x 0.07)
y_new=0.12+0.065
y_new=0.1865 m
So the new position is 0.1865 m
Answer:
The wavelength of the proton will be 
Explanation:
Given the speed of the proton is
of speed of light.
And the mass of the proton is
..
We need to find the wavelength of moving proton.
As we know the speed of the light 
So, speed of the proton will be

Now, we will use De Broglie's Equation to find out wavelength..

Where
is the wavelength
is the Planck's constant 
is the mass in kg
is the speed in m/s

So, the wavelength of the proton will be 
You’re using more force to kick the brick than to push it gently.
Answer:
Explanation:
Since the sound bouncing back from car has greater frequency , the car must be moving towards the police car . If v be the velocity of car
f = 
f is apparent frequency , f₀ is original frequency , V is velocity of sound and v is velocity of car
1270 = 
1.02419 = 
348.22-1.02419v =340 +v
2.02419v = 8.22
v = 4.06 m /s
B)
In this case , we shall take relative velocity in place of velocity of car .So
v = 20+4.06
= 24.06 m /s
f = 
= 
1240 x 
= 1428 Hz .