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mylen [45]
2 years ago
12

A window in a skyscraper has a surface area of 3.50 m2 Wind rushes by the outside of the window at 17.4 m/s, while inside the ai

r is stationary. What is the DIFFERENCE IN PRESSURE between the inside and outside?
Physics
1 answer:
ratelena [41]2 years ago
7 0

Answer:

Mark me as brain list plz

Explanation:

Using Bernoulli's Theorem

1/2 V12 +P1/d = 1/2V22 +P2/d

V1 = 17.4

V2 =0

1 /2 V12 = Pressure Difference / d

Where d = Density of air

Pressure Difference =( 1/2 V12) Density of air

Pressure Difference = 369.36

Force = Pressure difference * area = 369.36 *3.5 = 1292.8 N

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