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Finger [1]
2 years ago
8

Select the option below that contains the correct order or sequence of events. A) 1) Add host to subscription, 2) Use host as re

port source, 3) Scan hostB) 1) Use host as report source, 2) Add host to subscription, 3) Scan hostC) 1) Add host to subscription, 2) Scan host, 3) Use host as report sourceD) 1) Scan host, 2) Add host to subscription, 3) Use host as report source
Engineering
1 answer:
butalik [34]2 years ago
5 0

The  option that has the correct order or sequence of events are;

1) Scan host.

2) Add host to subscription.

3) Use host as report source.

<h3>What are host assets?</h3>

Host assets are known to be a kind of IP addresses in a person's account. This type of assets is one that can be used as a kind of  scan, map and also to report targets.

A person can view the hosts in their account by going the  Assets panel to  the Host Assets. One can add new hosts by the use of the New menu. The person can also only carry out actions like scanning, mapping and reporting on one's hosts.

Learn more about IP addresses from

brainly.com/question/24930846

You might be interested in
A gas has an initial volume o.25m^3, and absolute pressure 100kPa. Its initial temperature is 290k. The gas is compressed into a
dezoksy [38]

Answer:

<h2>698.3Kpa</h2>

Explanation:

Step one:

given data

V1=0.25m^3

T1=290k

P1=100kPa

V2=0.5m^2

T2=405k

P2=? final pressure

Step two:

The combined gas equation is given as

P1V1/T1=P2V2/T2

Substituting we have

(100*0.25)/290=P2*0.05/405

25/290=0.5P2/405

0.086=0.05P2/405

cross multiply

0.086*405=0.05P2

34.9=0.05P2

divide both sides by 0.05

P2=34.9/0.05

P2=698.3Kpa

<u>Therefore the new pressure is 698.3Kpa when the gas is compressed</u>

5 0
2 years ago
Recall the steps of the engineering design process. Compare and contrast the
Marta_Voda [28]

Answer:

hi

Explanation:

hiiiiiiiiiiiiiiiiiiiiiiiii

3 0
3 years ago
At an impaired driver checkpoint, the time required to conduct the impairment test varies (according to an exponential distribut
professor190 [17]

Answer:

Option (d) 2 min/veh

Explanation:

Data provided in the question:

Average time required = 60 seconds

Therefore,

The maximum capacity that can be accommodated on the system, μ = 60 veh/hr

Average Arrival rate, λ = 30 vehicles per hour

Now,

The average time spent by the vehicle is given as

⇒ \frac{1}{\mu(1-\frac{\lambda}{\mu})}

thus,

on substituting the respective values, we get

Average time spent by the vehicle = \frac{1}{60(1-\frac{30}{60})}

or

Average time spent by the vehicle = \frac{1}{60(1-0.5)}

or

Average time spent by the vehicle = \frac{1}{60(0.5)}

or

Average time spent by the vehicle = \frac{1}{30} hr/veh

or

Average time spent by the vehicle = \frac{1}{30}\times60 min/veh

[ 1 hour = 60 minutes]

thus,

Average time spent by the vehicle = 2 min/veh

Hence,

Option (d) 2 min/veh

7 0
3 years ago
with a digital system, if you have measured incorrectly and use too low of a kvp for adequate penetration, what do you need to d
Lubov Fominskaja [6]

The x-ray beam's penetrating power is regulated by kVp (beam quality). Every time an exposure is conducted, the x-rays need to be powerful (enough) to sufficiently penetrate through the target area.

<h3>How does kVp impact the exposure to digital receptors?</h3>

The radiation's penetration power and exposure to the image receptor both increase as the kVp value is raised.

<h3>Exposure to the image receptor is enhanced with an increase in kVp, right?</h3>

Due to an increase in photon quantity and penetrability, exposure at the image receptor rises by a factor of five of the change in kVp, doubling the intensity at the detector with a 15% change in kVp.

To know more about kVp visit:-

brainly.com/question/17095191

#SPJ4

5 0
1 year ago
we wish to send at a rate of 10Mbits/s over a passband channel. Assuming that an excess bandwidth of 50% is used, how much bandw
gayaneshka [121]

Answer:

QPSK: 7.5 MHz

64-QAM:2.5 MHz

64-Walsh-Hadamard: 160 MHz

Explanation:

See attached picture.

6 0
3 years ago
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