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tiny-mole [99]
2 years ago
12

I NEED HELP ASAP DUE IN 30 MINUTES!!!

Physics
2 answers:
Colt1911 [192]2 years ago
8 0
Answer is B

You scratch off a
You scratch off c
You scratch off d
Softa [21]2 years ago
6 0

Answer:

Explanation:It is commonly judged by how a vehicle performs particularly during cornering, acceleration, and braking as well as on the vehicle's directional stability when ...

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Convert 5.6kg to grams
OLEGan [10]

Answer:

my pleasure

Explanation:

5.6kg = 5600 grams

multiply the mass value by 1000

4 0
3 years ago
Read 2 more answers
WILL BE BRAINLIEST <br> HELP!!!
ivolga24 [154]

Answer:

(8.0÷6.0)×10[(-2)-(-3)]

6 0
2 years ago
a motorcycle accelerates from 15 m/s to 20 m/s over a distance of 50 meters. what is its average acceleration?
devlian [24]
For this, you need the v-squared equation, which is v(final)² = v(initial)² + 2aΔx The averate acceleration is thus a = (v(final)² - v(initial)²) / 2Δx = (20² - 15²) / 2(50) = 175 / 100 = 1.75 m/s² So the average acceleration is 1.75 m/s²
5 0
3 years ago
a hockey puck with a mass of 0.11 kg is at rest on the horizontal frictionless surface of the rink. a player applies a horizonta
stira [4]

The solution to this ques is available in the image.

Given,

Force= 1N

Mass= 0.11kg

Time= 5sec

Force= mass X accelaration

Accelaration= velocity/ time

Speed=distance/ time

Hence, the speed is 45 m/s and the distance is 225 m.

To know more about speed and distance problems the link is given below:

brainly.com/question/19610984?

#SPJ4

8 0
1 year ago
A physicist's right eye is presbyopic (i.e., farsighted). This eye can see clearly only beyond a distance of 97 cm, which makes
Ivan

Answer:

f = 19,877 cm   and  P = 5D

Explanation:

This is a lens focal length exercise, which must be solved with the optical constructor equation

        1 / f = 1 / p + 1 / q

where f is the focal length, p is the distance to the object and q is the distance to the image.

In this case the object is placed p = 25 cm from the eye, to be able to see it clearly the image must be at q = 97 cm from the eye

let's calculate

        1 / f = 1/97 + 1/25

        1 / f = 0.05

        f = 19,877 cm

the power of a lens is defined by the inverse of the focal length in meters

         P = 1 / f

         P = 1 / 19,877 10-2

         P = 5D

5 0
2 years ago
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