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2 years ago

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Suppose you are provided with a 35.83 g sample of potassium chlorate to perform this experiment. What is the mass of potassium c

hloride you expect to release upon heating?

1 answer:

Charra [1.4K]2 years ago

6 0

For a 35.83 g sample of potassium chlorate, the mass of potassium chloride is mathematically given as

M Kcl=21.62g

<h3>What is the mass of potassium chloride you expect to release upon heating?</h3>

Generally, the equation for the Chemical Reaction is mathematically given as

2KClO_3----->2KCl+2O_2

Therefore

$Mole of KCl=\frac{35.57}{122.55}$

Mole of KCl=0.29mol

Mass of Kcl=0.29*74.55

Mass of Kcl=21.62g

In conclusion, Mass of Kcl

M Kcl=21.62g

Read more about Chemical Reaction

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We could solve this using dimensional analysis as:

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Explanation:

Sodium hydroxide completely ionizes in water to produce sodium ions and hydroxide ions. Hydroxide ions are in excess and neutralize all acetic acid added by the following ionic equation:

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Construct a RICE table for the hydrolysis of $\text{Ac}^{-}$ under a basic aqueous environment (with a negligible hydronium concentration.)

$\begin{array}{cccccccc} \text{R} & \text{Ac}^{-}(aq) &+ & \text{H}_2\text{O}(aq) & \leftrightharpoons & \text{HAc}(aq) & + & \text{OH}^{-} (aq)\\ \text{I} & 0.10 \; \text{M} & & & & & &0.30 \; \text{M}\\ \text{C} & -x \; \text{M}& & & & +x \; \text{M}& & +x \; \text{M} \\ \text{E} & (0.10 - x) \; \text{M} & & & & x \; \text{M} & & (0.30 +x) \; \text{M} \end{array}$

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