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mixas84 [53]
2 years ago
7

Suppose you are provided with a 35.83 g sample of potassium chlorate to perform this experiment. What is the mass of potassium c

hloride you expect to release upon heating?
Chemistry
1 answer:
Charra [1.4K]2 years ago
6 0

For a 35.83 g sample of potassium chlorate,  the mass of potassium chloride is mathematically given as

M Kcl=21.62g

<h3>What is the mass of potassium chloride you expect to release upon heating?</h3>

Generally, the equation for the Chemical Reaction  is mathematically given as

2KClO_3----->2KCl+2O_2

Therefore

Mole of KCl=\frac{35.57}{122.55}

Mole of KCl=0.29mol

Mass of Kcl=0.29*74.55

Mass of Kcl=21.62g

In conclusion, Mass of Kcl

M Kcl=21.62g

Read more about Chemical Reaction

brainly.com/question/11231920

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natka813 [3]

Answer:

pH of the buffer solution is 1.76

Explanation:

To find the pH of a buffer we can use Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is -log Ka= 1.77 And [A⁻] is molar concentration of conjugate base, NaHSO₃ and [HA] molar concentration of weak acid, H₂SO₃</em>

<em />

Replacing values of the problem:

pH = 1.77 + log [0.304M] / [0.310M]

pH = 1.76

<h3>pH of the buffer solution is 1.76</h3>
4 0
3 years ago
What might happen when a gas is exposed to a small flame?
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Answer:

The fire may grow bigger, depending on the gas.

Explanation:

If you expose more air to a small flame then it could grow larger because air keeps fire alive.

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Translate the following chemical equation into a sentence. CH4+2O2 CO2+2H2O
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A gas sample occupies a volume of 1.264 L when the temperature is 168.0 °C and the pressure is 946.6 torr. How many molecules ar
alukav5142 [94]

Answer:

0.26×10²³ molecules

Explanation:

Given data:

Volume of gas = 1.264 L

Temperature = 168°C

Pressure = 946.6 torr

Number of molecules of gas = ?

Solution:

Temperature = 168°C (168+273= 441 K)

Pressure = 946.6 torr (946.6/760 = 1.25 atm)

Now we will determine the number of moles.

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1.25  atm ×1.264 L / 0.0821 atm.L/ mol.K   ×441 K

n = 1.58 /36.21 /mol

n = 0.044 mol

Now we will calculate the number of molecules by using Avogadro number.

1 mol = 6.022×10²³ molecules

0.044 mol × 6.022×10²³ molecules/ 1mol

0.26×10²³ molecules

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What is 30g(1mol÷70g)
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