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S_A_V [24]
2 years ago
8

What's ligand and how are they classified​

Chemistry
1 answer:
KATRIN_1 [288]2 years ago
8 0

Explanation:

<u>Ligands:</u> In co-ordination chemistry ligands are ion, molecule or any species which donates electron pair to central metal atom.

Depending on the type of interaction Ligands are of three types.

  1. Sigma donor only
  2. sigma as well as pi donor
  3. pi acceptor ligand

let's understand each type of Ligands individually & in more detail.

1 - Sigma donor only: This is a unidirectional interaction, in which filled ligand overlaps (head to head) with central metal atom/ion & donates pair of electron in the LUMO of metal.

generally all the molecules of 2nd period without pi bond comes in this category, below are few example of sigma donor ligands,

\small \sf NH_3, H_2O, CH_3^-, H^-, R-OH, R-NH_3, etc

2- Pi donor: This in also a unidirectional interaction between ligand & central metal atom but the along with head to head overlap, side overlapping takes place.

generally protonated neutral molecules who have more than one pair to donate show such interaction, for e.g.

NH3 have two lone pair to donate but the energy level of both the lone pairs are different hence when it is neutral it only donates one pair of electron. but when NH3 is protonated to NH2- it have two electron pairs (negative charge+ lone pair) to donate & both the pairs have same energy level. example of such ligands are below,

\sf \small NH_2^-, OH^-, R-O^-, R-NH^-, F^-, Cl^-, Br^- SH^- etc

3- Pi acceptor ligand: This is a bidirectional interaction between ligand & central metal atom/ion, the filled orbital of ligand undergoes head to head to overlap with vacant orbital of central metal atom, & filled D orbital of central metal donates their pair to vacant LUMO of ligand.

depending on the LUMO pi acceptor ligands are further classified into two categories.

d\pi - \sigma*   \small \sf When  \: lumo \:  is  \: \sigma*\\ d\pi - \pi*   \small \: \sf When  \: lumo  \: is  \: \pi*

The dπ-σ* is seen in molecules of 3rd period onwards without pi bond <em>for e.g.</em>

<em>PH3,</em><em> </em><em>PR</em><em>3</em><em>,</em><em> </em><em>AsR</em><em>3</em><em> </em><em>&</em><em> </em><em>SR</em><em>2</em><em> </em><em>etc</em>

The dπ-π* is seen in molecules of 2nd or3rd period with pi bond <em>for e.g.</em>

CO C N- SC N^- etc

<em><u>Thanks for joining brainly community!</u></em>

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What would happen to the rate of a reaction with rate law rate = k [NO]^2[H2] if
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The rate of a reaction would be one-fourth.

<h3>Further explanation</h3>

Given

Rate law-r₁ = k [NO]²[H2]

Required

The rate of a reaction

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.  

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\large{\boxed{\boxed{\bold{v~=~-\frac{\Delta A}{\Delta t}}}}

or  

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The concentration of NO were halved, so the rate :

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Which quantity is equivalent to the product of the absolute index of refraction of water and the speed of light in water?
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<h3>What is the speed of light?</h3>

Speed of light is the rate of speed though the light travels. To find the speed of light in any medium, the following formula is used.

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Here, (n) is the index of reaction and (c) is the speed of light in the vacuum. The speed of light in the vacuum is almost equal to the 3.0×10⁸ m/s.

Now the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water has to be find out.

The above formula can be written as,

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Here, the product of index of refraction and speed of light is equal to the speed of light in vacuum. This will be true for water as well.

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2 years ago
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monitta

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<h3>Further explanation</h3>

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Answer:

Hey did u get the answer I need ?!

Explanation:

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