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QveST [7]
2 years ago
14

What is the number of oxygen atoms in a formula unit of Al2(SO4)3?

Chemistry
2 answers:
Kamila [148]2 years ago
8 0

Answer:

First, we need to identify the elements in the compound. Elemental symbols are either formed of a capital letter or a capital letter followed by a lowercase letter. There are three different elements in this compound: Al, aluminum; S, sulfur; and O, oxygen. But we need to know how many atoms there are in a single unit of the compound. We need to use the subscript values, or lack thereof, to calculate this. The subscript two after Al indicates that one unit of the compound contains two aluminum atoms.

Let’s now look at the contents of the brackets. The subscript four after O tells us that there are four oxygen atoms. The absence of a subscript after S tells us that there is only one sulfur atom. But the entire bracket has the subscript three. Therefore, there’s actually a total of three sulfur atoms and 12 oxygen atoms. These numbers can actually be calculated by multiplying the subscripts for each atom within the brackets with the subscript on the outside of the brackets.

So there are two aluminum atoms, three sulfur atoms, and <u>12 oxygen atoms</u> in a single unit of the compound Al2(SO4)3.

<h3><u>Additional</u><u> </u><u>:</u><u>-</u></h3>

This sums to 17. Therefore, there are 17 atoms in a single unit of the compound Al2(SO4)3.

patriot [66]2 years ago
5 0

No of molecules of Aluminium trisulphate

  • 6.023×10²³

No of moles of each

  • Al=2
  • S=3
  • O=12

Total=17

So no of oxygen atoms

  • (6.023×10²³/17)×12
  • 4.25×10²³atoms
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What’s the physical properties of a molecular solid, in regards to its physical properties of formation?
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3 years ago
A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4
natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M

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