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anygoal [31]
3 years ago
12

A horizontal board of length 6.1 m and mass 12.8 kg rests on two supports. The first support is at one end of the board. The sec

ond support is at a distance of 2.38 m from the other end of the board. What force does this second support exert on the board

Physics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:102.84 N

Explanation:

Given

Mass of board m=12.8\ kg

Length of board l=6.1\ m

First support is at one end and second support is at a distance of 2.38 m from the other end

Suppose R_1 and R_2 are the reactions at the two support

Taking moment about the first end we can write

mg\times \dfrac{6.1}{2}-R_2(6.1-2.38)=0

R_2=\dfrac{12.8\times 9.8 \times 3.05}{3.72}

R_2=102.84\ N    

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