Question

A horizontal board of length 6.1 m and mass 12.8 kg rests on two supports. The first support is at one end of the board. The second support is at a distance of 2.38 m from the other end of the board. What force does this second support exert on the board

Answer 1

Answer:102.84 N

Explanation:

Given

Mass of board $m=12.8\ kg$

Length of board $l=6.1\ m$

First support is at one end and second support is at a distance of 2.38 m from the other end

Suppose $R_1$ and $R_2$ are the reactions at the two support

Taking moment about the first end we can write

$mg\times \dfrac{6.1}{2}-R_2(6.1-2.38)=0$

$R_2=\dfrac{12.8\times 9.8 \times 3.05}{3.72}$

$R_2=102.84\ N$