Brutus, a champion weight lifter, raises 220 kg a distance of 3.10 m. (a) how much work is done by brutus lifting the weights? j
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Answer: Hello the missing piece of your question is attached
question : Determine mass of steam that has entered ( in kg )
answer : 0.206 kg
Explanation:
V1 = 0.1 m^3 ,
v' = V1 / m1 = 0.1 / 0.6 = 0.167 m^3/kg
V2 = 0.2 m^3
using the steam tables
at ; P = 1000 kPa, v' = 0.167 m^3/kg
U1 = 2321 KJ/kg
at ; P = 1000 kPa , T2 = 280°C
v'2= 0.2481 m^3kg
U2 = 2760.6
at ; P = 5MPa , T = 500°C
h1 = 3434.7 KJ/Kg
calculate final mass ( m2 )
M2 = V2 / v'2
= 0.2 / 0.2481 = 0.806 kg
therefore the mass added = m2 - m1
= 0.806 - 0.6 = 0.206 kg
Answer:
Explanation:
Average velocity = Displacement/Time
ΔS = -10+6
ΔS = -4m
Given tme = 30s
Average velocity = -4/30
Average velocity = -0.13m/s
Average speed = Distance/Time
Total distance covered = 10m+6m
Total distance covered = 16m
Average speed = 16/30
Average speed = 0.53m/s
Answer:
Explanation:
The distance of Earth from the Sun is and of Mars from the Sun is
. Let assume that both planets have circular orbits. The centripetal accelaration can be found by using the following expression:
Since planet has translation at constant speed, this formula is applied to compute corresponding speeds:
Earth:
Mars:
Now, centripetal accelarations can be found:
Earth:
Mars:
The ratio of Earth's centripetal acceleration to Mars's centripetal acceleration is: