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4vir4ik [10]
3 years ago
4

While watching the clouds pass by, you notice a European swallow

Physics
1 answer:
RoseWind [281]3 years ago
0 0

Answer:

magnitude of angular momentum of the coconut after t = 1 s is

L = 1930.4 kg m^2/s

Explanation:

Since it is dropped at the instant when it is at overhead position

so we will have

v_x = 6.61 m/s

now vertical speed of the coconut after t = 1 s

v_y = 0 - gt

v_y = -9.8 m/s

now its displacement in x direction is given as

x = 6.61 (1) = 6.61 m

height of the coconut after t = 1 s

y = 21.4 - \frac{1}{2}gt^2

y = 21.4 - \frac{1}{2}(9.81)(1^2)

y = 16.5 m

now angular momentum is given as

L = \vec r \times m\vec v

now we have

L = (6.61 \hat i + 16.5 \hat j)\times (11.1)(6.61 \hat i - 9.81\hat j)

L = -719.8 \hat k - 1210.6\hat k

so magnitude of angular momentum of the coconut after t = 1 s is

L = 1930.4 kg m^2/s

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Do you think there might be a point in space between Earth and the Moon where the gravity of each would pull on an object equall
Firlakuza [10]

Answer: Yes.

Explanation:

Assuming Earth and Moon are isolated is space, it is possible to have a point where Earth and Moon will pull at an object with equal force.

That point will be closer to the Moon than the Earth because Moon's gravitational field strength is weaker than Earth's gravitational field strength.

7 0
4 years ago
What is the unit for molar mass?
dmitriy555 [2]

Answer:

kilogram per mole

Explanation:

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3 years ago
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5. A 500 kg satellite is in a circular orbit at an altitude of 500 km above the Earth's surface. Because of air friction, the sa
nika2105 [10]

Answer:

the energy transformed into internal energy is E fr = 1.57*10¹⁰ J

Explanation:

From energy conservation , the internal energy gained by friction should be equal to the loss of total energy of the satellite

Since the total energy of the satellite can be decomposed into kinetic and potential energy

E fr = ΔE = E₂-E₁

E₁=  K₁+V₁ = 1/2*m*v₁² + m*g*h₁

E₂ = K₂+V₂=  1/2*m*v₂² + m*g*h₂

first, we can choose our reference state so that h₂=0 and h₁=h=500 km

second , we can calculate the approximate the inicial velocity as the velocity required for a stable circular orbit

g = v₁²/(h+R) → v₁² = g*(h+R)

as the velocity diminishes, h diminishes, falling into the earth

assuming the radius of the Earth as R= 6371 km , then

v₁² = g*(h+R) = 9.8 m/s² * (500 km+ 6371 km) *1000 m/km = 6.73 * 10⁷ (m/s)²

replacing values

E₁ = 1/2*m*v₁² + m*g*h₁ = 1/2* 500kg *6.73 * 10⁷ (m/s)² + 500kg* 9.8m/s² * 500 km = 1.67*10¹⁰ J

E₂= 1/2*m*v₂² + m*g*h₂ =  1/2* 500kg *(2000 m/s)² + 0 = 1*10⁹ J

therefore

E fr = ΔE = E₂-E₁ = 1.67*10¹⁰ J - 1*10⁹ J = 1.57*10¹⁰ J  

5 0
4 years ago
One bright summer day a swimmer is floating with her head just above the surface of a large, clear lake where the water has inde
slavikrds [6]

Answer:

5.38035 m

Explanation:

n_w = Refactive index of water = 1.43

h = Depth = 5.5 m

Critical angle is given by

\theta_c=sin^{-1}\dfrac{1}{n_w}\\\Rightarrow \theta_c=sin^{-1}\dfrac{1}{1.43}\\\Rightarrow \theta_c=44.37^{\circ}

d = horizontal distance from the post where she no longer see the bottom of wooden post

So,

tan\theta_c=\dfrac{d}{h}\\\Rightarrow d=tan\theta_c\times h\\\Rightarrow d=tan44.37\times 5.5\\\Rightarrow d=5.38035\ m

The distance d is 5.38035 m

4 0
3 years ago
Determine the period of Saturns moon “Mimas”. Saturn has a mass of 5.68 x 10 to the 28th power kg and Mimas is about 1.87 x 10 t
nirvana33 [79]
n word on the florrr and dancing on the floor
7 0
3 years ago
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