Answer:
b.Beta
Explanation:
mass number remains constant while atomic number has been increased by 1 unit . beta is electron like element where its mass number is 0 and atomic number is -1.
For question 1:
A. Carbon, hydrogen, oxygen
Calcium, carbon, oxygen
Carbon, hydrogen
Carbon, hydrogen, oxygen
Silicon, oxygen
B. Carbon: 12, hydrogen: 22, oxygen: 11
Calcium: 1, Carbon: 1, oxygen: 3
Carbon:1, Hydrogen: 4
Carbon: 3, hydrogen: 8, Oxygen: 1
Silicon: 1 oxygen: 2
C. Table sugar: 45
Marble: 5
Natural gas: 5
Rubbing alcohol: 12
Glass: 3
For question 2: N2O
The correct answer is ionic radii increase.
The ionic radii decrease as one move across the periodic table, that is, from left to right, while the ionic radius increases as one move from top to bottom on the periodic table. As one moves down a group in the periodic table, the supplementary layers of electrons are being added that usually results in the increase of the ionic radius as one moves down the periodic table.
Answer:
The kinetic theory of matter (particle theory) says that all matter consists of many, very small particles which are constantly moving or in a continual state of motion. The degree to which the particles move is determined by the amount of energy they have and their relationship to other particles.
Six main points of the particle theory:
• All matter is made of particles.
• Particles have space between them.
• Particles are always moving.
• Particles move faster and get farther apart when heated.
• Particles are attracted to each other.
• All Particles of the same substance are identical
Given:
<span>BaO2(s) + 2 HCl(aq) => H2O2(aq) + BaCl2(aq)
</span>
Mass of barium peroxide = 1.49 g Volume of HCl solution = 25.1 mLConcentration of HCl solution = 0.0279 g HCl per mL
Solution: To determine the amount of hydrogen peroxide that would be produced, we use need to determine which is the limiting reactant and use the initial amount of this reactant for the calculations.
0.0279 g HCl / mL ( 25.1 mL ) ( 1 mol HCl / 36.46 g HCl) ( 1 mol BaO2 / 2 mol HCl ) = 0.0096 mol BaO2 needed
1.49 g BaO2 ( 1 mol / 169.3 g BaO2 ) ( 2 mol HCl / 1 mol BaO2 ) = 0.0176 mol HCl needed
Therefore, the limiting reactant would be barium peroxide since it is consumed completely first in the reaction.
1.49 g BaO2 ( 1 mol BaO2 / 169.3 g BaO2 ) ( 1 mol H2O2 / 1 mol BaO2 ) ( 34.02 g H2O2 / 1 mol H2O2 ) = 0.299 g H2O2