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inysia [295]
3 years ago
6

When a driver touches a car’s steering wheel on a hot day, heat is transferred to the driver’s hands by ___________?

Physics
2 answers:
Alik [6]3 years ago
8 0

The correct answer to this question is : C) Conduction

EXPLANATION:

Before coming into any conclusion, first we have to understand conduction.

Conduction is the mode of transmission of heat in which heat will flow from a body at high temperature to a body at low temperature in contact or from hotter part of the body to its colder part, without any actual transport of particles.

As per the question, the heat is transferred to driver's hand when he touches the steering wheel.

As there is actual contact between hand and steering wheel, the heat transmission will be conduction.

Anna [14]3 years ago
5 0
The heat is transferred by conduction because the driver touches the car by contacting, the heat is transferred from hot to cold.
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Do all objects fall at the same rate?and if they do not why?
Tema [17]
No, I heavier object will fall much faster than something lighter than it. This is because it’s more dense and hard so it can cut through the air particles quicker than a lighter object which takes longer to cut through the air and fall

Example:

A rock vs a feather
The rock will fall quicker because it’s more dense and falls straight down and the feather will be slower because it flows slowly down through the air particles
6 0
3 years ago
How is acceleration calculated?
steposvetlana [31]

Answer:

Acceleration is the change in velocity divided by time

Explanation:

This is the correct answer because distance divided by time is the position. Speed multiplied by time is the distance. And acceleration is not just velocity, but the change in velocity over time.

4 0
3 years ago
Read 2 more answers
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
spayn [35]

To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

\theta = \frac{1.22 \lambda }{D}

Here,

D is diameter of the eye

D = \frac{1.22 (539nm)}{5.11 mm}

D= 1.287*10^{-4}m

The angle that relates the distance between the lights and the distance to the lamp is given by,

Sin\theta = \frac{d}{L}

For small angle, sin\theta = \theta

sin \theta = \frac{d}{L}

Here,

d = Distance between lights

L = Distance from eye to lamp

For small angle sin \theta = \theta

Therefore,

L = \frac{d}{sin\theta}

L = \frac{0.691m}{1.287*10^{-4}}

L = 5367m

Therefore the distance is 5.367km.

4 0
3 years ago
a runner starts from rest and has an acceleration of 3 m/s^2. How fast is she running after 1.1 seconds
grigory [225]
Acceleration x time = velocity 

Since you're given acceleration and time, just plug the values into the equation. 

3\frac{m}{s^{2}} x 1.1 s = ? 

Solve that equation, and remember your velocity should be in m/s.
8 0
3 years ago
A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,
muminat

Answer:

The speed of the plank relative to the ice is:

v_{p}=-0.33\: m/s

Explanation:

Here we can use momentum conservation. Do not forget it is relative to the ice.

m_{g}v_{g}+m_{p}v_{p}=0 (1)

Where:

  • m(g) is the mass of the girl
  • m(p) is the mass of the plank
  • v(g) is the speed of the girl
  • v(p) is the speed of the plank

Now, as we have relative velocities, we have:

v_{g/b}=v_{g}-v_{p}=1.55 \: m/s (2)

v(g/b) is the speed of the girl relative to the plank

Solving the system of equations (1) and (2)

45v_{g}+168v_{p}=0

v_{g}-v_{p}=1.55

v_{p}=-0.33\: m/s

I hope it helps you!      

8 0
3 years ago
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