Ask question

Ask question

All categories

Zielflug [23.3K]

2 years ago

13

A wire carrying a current is bent into a loop. The magnetic field is strongest A. at the center of the loop. B. at the edges of

the loop. C. where the loop is located.

2 answers:

Tems11 [23]2 years ago

7 0

C is the direction of the current flow

Maru [420]2 years ago

3 0

Your answer is a. at the center of the loop

You might be interested in

When velocity is positive and acceleration is negative, what happens to the object’s motion?

xenn [34]

Answer:

Option (D) : The object slows down.

4 0

2 years ago

Differentiate between center of mass and center of gravity

ELEN [110]

Answer:

Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field. Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.

Explanation:

google

3 0

3 years ago

A car traveling at 27.4 m/s hits a bridge abutment. A passenger in the car, who has a mass of 65.0 kg, moves forward a distance

Minchanka [31]

Answer:

$F=43570.9N$

Explanation:

We can calculate the acceleration experimented by the passenger using the formula $v_f^2=v_i^2+2ad$ , taking the initial direction of movement as the positive direction and considering it comes to a rest:

$a=\frac{v_f^2-v_i^2}{2d}=\frac{-v_i^2}{2d}$

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

$F=ma=\frac{-mv_i^2}{2d}$

Which for our values is:

$F=\frac{-(65kg)(27.4m/s)^2}{2(0.56m)}=43570.9N$

6 0

3 years ago

Objects at the "Human Scale" are held in their shapes primarily by which force:

Cerrena [4.2K]

D. Electrical is the answer

5 0

2 years ago

Read 2 more answers

A quarterback throws a football toward a receiver with an initial speed of 20 m/s at an angle of 30∘ above the horizontal. At th

lana66690 [7]

Answer:

a) In order to catch the ball at the level at which it is thrown in the direction of motion.

b)Speed of the receiver will be 7.52m/s

Explanation:

Calculating range,R= Vo^2Sin2theta/g

R= (20^2×Sin(2×30)/9.8 = 35.35m

Let receiver be(R-20) = 35.35-20= 15.35m

The horizontal component of the ball is:

Vox= Vocostheta= 20× cos30°

Vox= 17.32m/s

Time taken to coverR=35.35m with 17.32m/s will be:

t=R/Vox= 35.35/17.32

t= 2.04seconds

b)Speed required to cover 15.35m at 2.04seconds

Vxreciever= d/t = 15.35/2.04 = 7.52m/s

7 0

2 years ago

Read 2 more answers