The ball will take 0.45 seconds to reach the ground
<h3>How will we solve this question?</h3>
We will use Newton’s laws of motion, so
H= 
taking height= 1m
<h3>What are the three laws of motion given by Newton?</h3>
The 3 laws of motion given by Newton are as follows:
1) Unless an unbalanced force acts upon it, an item at rest remains at rest, and an object in motion continues to move in a straight line at a constant pace.
2) An object's acceleration is influenced by its mass and the force being applied.
3) Whenever one thing applies force to another, the second object applies the opposing, equal force to the first.
To know more about Newton's laws of motion visit:
brainly.com/question/27915475
#SPJ4
We know, a = v/t
Here, a = 5 m/s²
v = 50 km/h= 13.88 m/s
Substitute their values into the expression:
5 = 13.88 / t
t = 13.88/5
t = 2.78 sec
Now, we know, v = d/t
13.88 = d/2.78
d = 13.88 * 2.78
d = 38.53 meter
In short, Your Answers would be:
i) It will take 2.78 sec
ii) It will travel for 38.53 m after a brakes applied.
Hope this helps!
Answer:
yᵢ = h
vᵢᵧ = 0
Explanation:
Let initial velocity = u
final velocity = v
height = h
acceleration due to gravity = g
Therefore fro equation of motion,
Here initial velocity is zero.
Hence, 
but since it points downward and you positive is taken in the up direction
Answer:
solute + solvent = solution
Explanation:
solute is <em>Any substance that is dissolved in a liquid solvent to create a solution</em>
solvent is <em>A liquid that dissolves a solid, liquid, or gaseous solute, resulting in a solution.</em>
and.
solution is <em>A homogeneous mixture, which may be liquid, gas or solid, formed by dissolving one or more substances.</em>
b). The power depends on the RATE at which work is done.
Power = (Work or Energy) / (time)
So to calculate it, you have to know how much work is done AND how much time that takes.
In part (a), you calculated the amount of work it takes to lift the car from the ground to Point-A. But the question doesn't tell us anywhere how much time that takes. So there's NO WAY to calculate the power needed to do it.
The more power is used, the faster the car is lifted. The less power is used, the slower the car creeps up the first hill. If the people in the car have a lot of time to sit and wait, the car can be dragged from the ground up to Point-A with a very very very small power ... you could do it with a hamster on a treadmill. That would just take a long time, but it could be done if the power is small enough.
Without knowing the time, we can't calculate the power.
...
d). Kinetic energy = (1/2) · (mass) · (speed squared)
On the way up, the car stops when it reaches point-A.
On the way down, the car leaves point-A from "rest".
WHILE it's at point-A, it has <u><em>no speed</em></u>. So it has no (<em>zero</em>) kinetic energy.
