Question

Based on following data, Angular acceleration of the tibia 450 rad/sec 2 The mass moment of inertia for the tibia is 0.40 Nm sec 2 The perpendicular distance between patellar tendon and the center of rotation is 0.045m Determine the muscle force acting on patellar tendon. Show all works

Answer 1

Answer:

4000 N

Explanation:

We have given angular acceleration $\alpha =450rad/sec^2$

Moment of inertia = 0.40 Nm

The distance d from the center of rotation is $d=0.045 m$

We have to find the muscle force F

From torque equation we know that $Fd=I\alpha$

$F\times 0.045=0.40\times 450$

$F=4000\ N$