Answer: Mass of water produced is 17.3 grams
Explanation:
To calculate the number of moles, we use the equation:
.....(1)
For benzene:
Given mass of benzene = 25.0 g
Molar mass of benzene= 78 g/mol
Putting values in equation 1, we get:
![\text{Moles of benzene}=\frac{25.0g}{78g/mol}=0.32mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20benzene%7D%3D%5Cfrac%7B25.0g%7D%7B78g%2Fmol%7D%3D0.32mol)
The chemical equation for the reaction follows:
![2C_6H_6(g)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)](https://tex.z-dn.net/?f=2C_6H_6%28g%29%2B15O_2%28g%29%5Crightarrow%2012CO_2%28g%29%2B6H_2O%28l%29)
As, oxygen is an excess reagent. Thus benzene is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of benzene produces 6 moles of water
So, 0.32 moles of benzene will produce =
of water
Now, calculating the mass of water from equation 1, we get:
Molar mass of water= 18 g/mol
Moles of water = 0.96moles
Putting values in equation 1, we get:
![0.96mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=17.3g](https://tex.z-dn.net/?f=0.96mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20water%7D%7D%7B18g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20water%7D%3D17.3g)
Thus mass of water produced is 17.3 grams