All categories

3 years ago

A cart being pulled with 30N through a 2 m hallway over two seconds. How does it have the greatest power exerted on it

Physics

1 answer:

Lapatulllka [165]3 years ago

7 0

Answer:

Power = 30 [watts]

Explanation:

Initia data:

F = force = 30[N]

d = displacement = 2 [m]

By definition we know that work is equal to the product of force by the distance displaced

Therefore:

W = F * d = 30 * 2

W = 60 [J]

And power is defined as the amount of work done in a given time interval

time = t = 2 [sec]

Power = W / t

Power = 60 / 2

Power = 30 [W]

You might be interested in

What is the equivalent volume occupied by three milliliters of water?

goldenfox [79]

Three cubic centimeters

7 0

3 years ago

Read 2 more answers

Describe two reasons why scientists are looking for alternatives to fossil fuels

Evgesh-ka [11]

1) It is because they produce a lot of pollution in the atmosphere
2) They are limited in number and can't be recycled

Hope this helps!

3 0

3 years ago

In what way did scientists Jonas Salk and Albert Sabin influence society? They generated plastics for increased manufacturing. T

faltersainse [42]

They discovered a vaccine to reduce illnesses, specifically Polio and Influenza. The work of Salk and Sabin has almost eradicated what was once a deadly disesase ( polio) . For example, there were 350,000 deaths related to poliovirus across the world in 1988 and they reduced to 22 in 2017. Also, their work has saved millions of lives from polio induced paralysis

3 0

3 years ago

Read 2 more answers

An object thrown vertically upward from the surface of a celestial body at a velocity of 36 m/s reaches a height of sequalsminu

Anarel [89]

Answer:

v = -1.8t+36

20 seconds

360 m

40 seconds

36 m/s

The object speed will increase when it is coming down from its highest height.

Explanation:

$s=-0.9t^2+36t$

Differentiating with respect to time we get

$\frac{ds}{dt}=-1.8t+36\\\Rightarrow v=-1.8t+36$

a) Velocity of the object after t seconds is v = -1.8t+36

At the highest point v will be 0

$0=-1.8t+36\\\Rightarrow t=\frac{-36}{-1.8}\\\Rightarrow t=20\ s$

b) The object will reach the highest point after 20 seconds

$s=-0.9t^2+36t\\\Rightarrow s=-0.9\times 20^2+36\times 20\\\Rightarrow s=360\ m$

c) Highest point the object will reach is 360 m

$s=-0.9t^2+36t\\\Rightarrow 360=-0.9t^2+36t\\\Rightarrow -0.9t^2+36t-360=0\\\Rightarrow -9t^2+360t-3600=0$

$\frac{-360\pm \sqrt{0}}{2\left(-9\right)}\\\Rightarrow t=20\ s$

d) Time taken to strike the ground would be 20+20 = 40 seconds

$[tex]v=u+at\\\Rightarrow v=0+0.9\times 2\times 20\\\Rightarrow v=36\ m/s$

Acceleration will be taken as positive because the object is going down. Hence, the sign changes. 2 is multiplied because the expression is given in the form of $s=ut+\frac{1}{2}at^2$

e) The velocity with which the object strikes the ground will be 36 m/s

f) The speed will increase when the object has gone up and for 20 seconds and falls down for 20 seconds. The object speed will increase when it is coming down from its highest height.

4 0

3 years ago

Help pls they are all going to have the same answers.

Liula [17]

1.activities of daily living.
2.activity of daily living.
3.planned exercises activities.
4. planned exercises activities.
5. activities of daily living.
6. planned exercises activities.

4 0

3 years ago