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tiny-mole [99]
3 years ago
7

A cart being pulled with 30N through a 2 m hallway over two seconds. How does it have the greatest power exerted on it

Physics
1 answer:
Lapatulllka [165]3 years ago
7 0

Answer:

Power = 30 [watts]

Explanation:

Initia data:

F = force = 30[N]

d = displacement = 2 [m]

By definition we know that work is equal to the product of force by the distance displaced

Therefore:

W = F * d = 30 * 2

W = 60 [J]

And power is defined as the amount of work done in a given time interval

time = t = 2 [sec]

Power = W / t

Power = 60 / 2

Power = 30 [W]

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A 900-kg car cruising at a constant speed of 60 km/h is to accelerate to 100 km/h in 4 s. The additional power needed to achieve
kiruha [24]

To solve this problem we will apply the concepts related to power as a function of the change of energy with respect to time. But we will consider the energy in the body equivalent to kinetic energy. The change in said energy will be the difference between the two velocity data given by half of the mass. We will first convert the given units into an international system like this

Initial Velocity,

V_i = 60km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

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Final Velocity,

V_f = 100km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

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