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tiny-mole [99]
3 years ago
7

A cart being pulled with 30N through a 2 m hallway over two seconds. How does it have the greatest power exerted on it

Physics
1 answer:
Lapatulllka [165]3 years ago
7 0

Answer:

Power = 30 [watts]

Explanation:

Initia data:

F = force = 30[N]

d = displacement = 2 [m]

By definition we know that work is equal to the product of force by the distance displaced

Therefore:

W = F * d = 30 * 2

W = 60 [J]

And power is defined as the amount of work done in a given time interval

time = t = 2 [sec]

Power = W / t

Power = 60 / 2

Power = 30 [W]

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Explanation:

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3 years ago
A element source has a decayed constant of 13.6pico per second. Calculate the half life of this element. ​
vladimir1956 [14]

Answer:

5.1 x 10¹⁰s

Explanation:

Given parameters:

Decay constant  = 13.6 x 10⁻¹²/s

Unknown:

Half life of the element  = ?

Solution:

From the decay constant, we can find the half-life of this radioactive element.

  Half-life  = \frac{0.693}{decay constant}  

     Half-life  = \frac{0.693}{13.6 x 10^{-12} }   = 5.1 x 10¹⁰s

4 0
3 years ago
Distinguish between the two main types of mechanical waves
jenyasd209 [6]

Explanation:

Mechanical waves are waves that requires a medium for their propagation. There are two types of mechanical waves:

  • Transverse waves
  • Longitudinal waves

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Longitudinal waves are waves that propagates parallel to their source. They move in a series of rarefactions and compressions along their path. An example is seismic p-waves

5 0
3 years ago
How much work (MJ) must a car produce to drive 125 miles if an average force of 306 N must be maintained to overcome friction?
baherus [9]

Answer:

The right solution is "61.557 MJ". A further explanation is given below.

Explanation:

The given values are:

Force,

F = 306 N

Drive,

D = 125 miles,

i.e.,

  = 201168

meters

As we know,

The work done will be:

= F\times S

On substituting the given values, we get

= 306\times 201168

= 61557408 \ J

On converting it in "MJ", we get

= 61.557\times 10^6 \ J

= 61.557 \ MJ

6 0
3 years ago
The force of replusion between two like charged particles will increase if​
Alex_Xolod [135]

Answer:

The distance of separation is decreased

Explanation:

From Cuolomb's law, we know that the strength of charge is inversely proportional to the distance of separation between the charges. To mean that increasing the distance let's say from 2m to 3 m would mean initial strength getting form 1/4 to 1/9 which is a decrease. The vice versa is true hence the force of repulsion can increase only when we decrease the distance of separation.

7 0
3 years ago
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