The absorbance reported by the defective instrument was 0.3933.
Absorbance A = - log₁₀ T
Tm = transmittance measured by spectrophotometer
Tm = 0.44
Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654
True absorbance can be calculated by true transmittance, Tm = T+S(α-T)
S = fraction of stray light = 6%= 6/100 = 0.06
α= 1, ideal case
T = true transmittance of the sample
Tm = T+S(α-T)
now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233
therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)
i.e; 0.3933
To know more about transmittance click here:
brainly.com/question/17088180
#SPJ4
Answer:
I don't know
Explanation:
pls I need a little bit answer
Answer:
it’s D. to reduce indigestion
Explanation:
Answer:
978.19° C
Explanation:
P1V1/T1 =P2V2/T2 Since the pressure is constant, this can be written as
V1/T1 = V2/T2 RE-ARRANGE TO
V2 * T1/V1 = T2 Note: T must be in Kelvin!!
1.5 L * (273.15 + 23) / (.355 L ) = T2 = 1251.338 K =978.19 C
I can tell you there certainly is enough information, so we can eliminate the fourth option right away.
Group two elements tend to form 2+ cations, and nitrogen forms 3- anions. To make a stable substance, we need those to cancel out. Calling the group 2 element X:
N2X3 would cause the charge to be 2(-3) + 3(2) = 0
This would mean 3 ions of X and 2 anions of N would be a stable ionic compound.
