the answer is true the first one
Answer:
There is no formation of shmoos
Explanation:
If the hypothesis that says "Fus3 kinase is required for the signal transduction pathway leading shmoo formation" is correct, then a strain with a deletion Fus3, is not going to render Fus3 kinase, at least active. By this reason, there will not be shmoo formation
A qualitative test for sulfate in alum crystals using ionic reactions of barium chloride (BaCl2) is given Ba²⁺(aq) + SO₄²⁻ (aq) → BaSO₄(s).
<h3>What is qualitative test?</h3>
Qualitative test measures changes in color, melting point, odor, reactivity, radioactivity, boiling point, bubble production, and precipitation of the sample.
<h3>Qualitative test for sulfate in alum crystals </h3>
When an aqueous solution of a barium salt (BaCl₂) is mixed with an aqueous solution containing sulfate, a white precipitate of insoluble BaSO₄ forms according to the net ionic equation given below;
Ba²⁺(aq) + SO₄²⁻ (aq) → BaSO₄(s)
Thus, a qualitative test for sulfate in alum crystals using ionic reactions of barium chloride (BaCl2) is given Ba²⁺(aq) + SO₄²⁻ (aq) → BaSO₄(s).
Learn more about qualitative test here: brainly.com/question/2109763
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Given :
Concentration of product [A] = 0.371 M .
Rate constant ,
.
To Find :
The rate for the reaction .
Solution :
We know , for second order reaction , rate is given by :
![r=k[A]^2\\\\r=0.761\times 0.371^2\ M/t\\\\r=0.10\ M/t](https://tex.z-dn.net/?f=r%3Dk%5BA%5D%5E2%5C%5C%5C%5Cr%3D0.761%5Ctimes%200.371%5E2%5C%20M%2Ft%5C%5C%5C%5Cr%3D0.10%5C%20M%2Ft)
Therefore , the rate for the second order reaction is 0.1 M/t .
Hence , this is the required solution .