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3 years ago

What is computer programming

Engineering

1 answer:

Vikki [24]3 years ago

3 0

Answer:

Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.

Explanation:

Hope dis helps! :)

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26 V is measured across a 220 Ω resistance. This means that resistor current equals ________. Group of answer choices 1.2 A 57 A

zysi [14]

You can use ohm’s law
I=V/R

3 0

3 years ago

For each of the following pairs of polymers, do the following: (1) State whether it is possible to determine whether one polymer

Vinvika [58]

Answer:

1). Linear and syndiotactic poly(vinyl chloride); linear and isotactic polystyrene

2). Network phenol-formaldehyde; linear and heavily crosslinked cis-isoprene

3). Linear polyethylene, lightly branched isotactic polypropylene

Explanation:

1). It is very much possible to decide for the two polymers. Here the linear as well as the syndiotactic poly(vinyl chloride) are likely to be crystallize; the side - group phenyl of the polystyrene is more bulkier than CI side group for the poly(vinyl chloride). The syndiotactic as well as the isotactic isomers are likely to crystallize equally.

2). No we cannot decide for the two polymers. Both of them are crosslinked and the network polymers may not crystallize.

3). It is a possible to decide the two polymers. The linear polyethylene is likely to crystallize.

3 0

3 years ago

(Gas Mileage) Drivers are concerned with the mileage their automobiles get. One driver has kept track of several trips by record

Effectus [21]

Answer:

import java.util.*;

public class Main {

public static void main(String[] args) {

double milesPerGallon = 0;

int totalMiles = 0;

int totalGallons = 0;

double totalMPG = 0;

Scanner input = new Scanner(System.in);

while(true){

System.out.print("Enter the miles driven: ");

int miles = input.nextInt();

if(miles <= 0)

break;

else{

System.out.print("Enter the gallons used: ");

int gallons = input.nextInt();

totalMiles += miles;

totalGallons += gallons;

milesPerGallon = (double) miles/gallons;

totalMPG = (double) totalMiles / totalGallons;

System.out.printf("Miles per gallon for this trip is: %.1f\n", milesPerGallon);

System.out.printf("Total miles per gallon is: %.1f\n", totalMPG);

}

Explanation:

Initialize the variables

Create a while loop that iterates until the specified condition is met inside the loop

Inside the loop, ask the user to enter the miles. If the miles is less than or equal to 0, stop the loop. Otherwise, for each trip do the following: Ask the user to enter the gallons. Add the miles and gallons to totalMiles and totalGallons respectively. Calculate the milesPerGallon (divide miles by gallons). Calculate the totalMPG (divide totalMiles by totalGallons). Print the miles per gallon and total miles per gallon.

6 0

3 years ago

A rigid tank of volume of 0.06 m^3 initially contains a saturated mixture of liquid and vapor of H2O at a pressure of 15 bar and

Serga [27]

Answer:

The total mass in the tank = 0.45524 kg

The amount of heat transferred = 3426.33 kJ

Explanation:

Given that:

The volume of the tank V = 0.06 m³

The pressure of the liquid and the vapor of H2O (p) = 15 bar

The initial quality of the mixture $\mathbf{x_{initial} - 0.20}$

By applying the energy rate balance equation;

$\dfrac{dU}{dt} = Q_{CV} - m_eh_e$

where;

$m_e =- \dfrac{dm_{CV}}{dt}$

Thus, $\dfrac{dU}{dt} =Q_{CV} + \dfrac{dm_{CV}}{dt}h_e$

If we integrate both sides; we have:

$\Delta u_{CV} = Q_{CV} + h _e \int \limits ^2_1 \ dm_{CV}$

$m_2u_2 - m_1 u_1 = Q_{CV} + h_e (M_2-m_1) \ \ \ --- (1)$

We obtain the following data from the saturated water pressure tables, at p = 15 bar.

Since:

$h_e =h_g$

Then: $h_g = h_e = 2792.2 \ kJ/kg$

$v_f = 1.1539 \times 10^{-3} \ m^3 /kg$

$v_g = 0.1318 \ m^3/kg$

Hence;

$v_1 = v_f + x_{initial} ( v_g-v_f)$

$v_1 = 1.1529 \times 10^{-3} + 0.2 ( 0.1318-1.159\times 10^{-3} )$

$v_1 = 0.02728 \ m^3/kg$

Similarly; we obtained the data for $u_f \ \& \ u_g$ from water pressure tables at p = 15 bar

$u_f = 843.16 \ kJ/kg\\\\ u_g = 2594.5 \ kJ/kg$

Hence;

$u_1 = u_f + x_{initial } (u_g -u_f)$

$u_1 =843.16 + 0.2 (2594.5 -843.16)$

$u_1 = 1193.428$

However; the initial mass $m_1$ can be calculated by using the formula:

$m_1 = \dfrac{V}{v_1}$

$m_1 = \dfrac{0.06}{0.02728}$

$m_1 = 2.1994 \ kg$

From the question, given that the final quality; $x_2 = 1$

$v_2 = v_f + x_{final } (v_g - v_f)$

$v_2 = 1.1539 \times 10^{-3} + 1(0.1318 -1.1539 \times 10^{-3})$

$v_2 = 0.1318 \ m^3/kg$

Also;

$u_2 = u_f + x_{final} (u_g - u_f)$

$u_2 = 843.16 + 1 (2594.5 - 843.16)$

$u_2 = 2594.5 \ kJ/kg$

Then the final mass can be calculated by using the formula:

$m_2 = \dfrac{V}{v_2}$

$m_2 = \dfrac{0.06}{0.1318}$

$m_2 = 0.45524 \ kg$

Thus; the total mass in the tank = 0.45524 kg

FInally; from the previous equation (1) above:

$m_2u_2 - m_1 u_1 = Q_{CV} + h_e (M_2-m_1) \ \ \ --- (1)$

$Q = (m_2u_2-m_1u_1) - h_e(m_2-m_1)$

Q = [(0.45524)(2594.5) -(2.1994)(1193.428)-(2792.2)(0.45524-2.1994)]

Q = [ 1181.12018 - 2624.825543 - (2792.2)(-1.74416 )]

Q = 3426.33 kJ

Thus, the amount of heat transferred = 3426.33 kJ

7 0

3 years ago

25 points

Nikitich [7]

Answer:

D. Rectangular

Explanation:

This is because rectangular coordinate systems are used in plotting common straight lines graphs with the formulae,

Y = Mx + c

Where y is the vertical coordinate

X is the horizontal coordinate

M is the dlope of the line

C is the y-axis intercept

3 0

3 years ago

Read 2 more answers