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Advocard [28]
3 years ago
9

Please help me look at the image below

Physics
1 answer:
djverab [1.8K]3 years ago
7 0
I can’t see anything
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Is the voltage of two identical lamps the same?​
Dahasolnce [82]

Answer:

It depends if they have the same lightbulb in them.

Explanation:

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Which person will most likely hear the loudest sound?
Nataliya [291]

Person standing on A will hear the loudest sound

Explanation:

The intensity of a sound wave (which is proportional to the loudness of the sound) follows an inverse square law, which is:

I\propto \frac{1}{r^2}

where

I is the intensity of the wave

r is the distance from the source of the sound

This equation means that the intensity of the sound wave (and therefore, its loudness) is inversely proportional to the square of the distance  from the source: therefore,

  • As we get closer to the source of sound, the loudness increases
  • As we move away from the source of sound, the loudness decreases

Therefore, the person that will hear the loudest sound is the one standing closer to the source, and therefore person A.

Learn more about sound waves:

brainly.com/question/4899681

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3 years ago
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The force exerted by the earth on a body is called ______of a body.
AVprozaik [17]

Answer:

The force exerted by the earth on a body is called gravitational of a body.

i think this is the answer

4 0
3 years ago
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An object is thrown directly downward from the top of a very tall building. The speed of the object just as it is released is 17
Softa [21]

Answer:

distance cover is  = 102.53 m

Explanation:

Given data:

speed of object is 17.1 m/s

t_1 = 3.32 sec

t_2 = 5.08 sec

from equation of motion we know that

d_1 = vt_1 + \frac{1}{2} gt_1^2

where d_1 is distance covered in time t1

sod_1 = 17.1 \times 3.32 + \frac{1}{2} 9.8 \times 3.32^2=

d_1 = 110.78 m

d_2 = vt_2 + \frac{1}{2} gt_2^2

where d_2 is distance covered in time t2

d_2 = 17.1 \times 5.08 + \frac{1}{2}\times9.8 \times 5.08^2

d_2 = 213.31 m

distance cover is  = 213.31 - 110.78 = 102.53 m

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3 years ago
If a 4N weight is hung on a spring, and it extends by 0.2m, what is the spring constant (k)?
Naddika [18.5K]

Answer: 200 N/m

Explanation:

The Gravitational spring energy(Us) is equal to 1/2kx^2. So we have x as .2 m and Us as 4 N. So 4 N = 1/2 * k * .2^2. So now we solve for K and get 200 N/m.

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