Please help me look at the image below

Many fitness programs include weight training, which A. can be used in place of aerobic exercise, when done regularly. B. helps

11Alexandr11 [23.1K]

The answer would be C) because weight lifting is used to increase your muscular strength, and that's why you try and add more weight during sessions, so it's not too easy for you and you can build a higher endurance.

6 0

3 years ago

An athlete stretches a spring an extra 40.0 cm beyond its initial length. how much energy has he transferred to the spring, if t

marissa [1.9K]

The energy transferred to the spring is given by:
$U= \frac{1}{2}kx^2$
where
k is the spring constant
x is the elongation of the spring with respect its initial length

Let's convert the data into the SI units:
$k=52.9 N/cm = 5290 N/m$
$x=40.0 cm=0.4 m$

so now we can use these data inside the equation ,to find the energy transferred to the spring:
$U= \frac{1}{2}kx^2= \frac{1}{2}(5290 N/m)(0.4m)^2=423.2 J$

4 0

3 years ago

The speed of an electromagnetic wave is a constant, 3.0 × 108 m/s. The wavelength of a wave is 0.3 meters. What is the frequency

mojhsa [17]

It would be 1.0 x 10^6 Hz

6 0

3 years ago

Read 2 more answers

Who exerts more pressure? a) A girl of 50 kg, wearing heels with an area of 1 cm2. b) An elephant of 4000 kg with foot area of 2

Mrrafil [7]

Answer:

The girl exerts more pressure.

Explanation:

Pressure can be defined as the force exerted normally or perpendicularly per unit area.

i.e P = F/A

Girls

Area of the heel = 1cm² = 10^(-4) m²

Force = mg = 50 × 10 = 500N

Pressure =

$\frac{500}{10 ^{ - 4} }$

$= 5 \times {10}^{6}$

Elephant

Area = 250cm² = 2.5 x 10^(-2)b m²

Force = mg = 40000N

Pressure =

$\frac{40000}{2.5 \times {10}^{ - 2} }$

$= 1.6 \times {10}^{6}$

5 0

3 years ago

8. A gas is contained in a horizontal piston-cylinder apparatus at a pressure of 350 kPa and a volume of 0.02 m3 . Determine the

ikadub [295]

Answer:

45500 J

Explanation:

Pressure, P =350 kPa = 350 x 1000 Pa

V1 = 0.02 m^3

V2 = 0.15 m^3

Work done by the piston

W = Pressure x increase in volume

W = P x (V2 - V1)

W = 350 x 1000 (0.15 - 0.02)

W = 45500 J

Thus, the work done is 45500 J.

7 0

3 years ago