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Lerok [7]
2 years ago
9

Two diodes are in series. The first diode has a voltage of 0.75 V and the second has a voltage of 0.8 V. If the current through

the first diode is 400 mA, then the current through the second diode is _____ mA.
Physics
1 answer:
tensa zangetsu [6.8K]2 years ago
6 0

The current in the second diode is 400mA

Data;

  • First Voltage = 0.75V
  • Second Voltage = 0.8V
  • First Current (I) = 400mA
  • Second Current(I) = ?
<h3>Current In a Series</h3>

The current in the first diode is equal to 400mA. In a series circuit, the current passing the diodes are equal. This implies that the current in the series are equal.

Diodes connected in series will be the equal.

I_1 = I_2

Since I1 is 400mA, I2 will be equal to 400mA

I_1 = I_2\\I_1 = 400mA\\I_2 = 400mA

The current in the second diode is 400mA

Learn more on current in a diode here;

brainly.com/question/1455378

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