Question

Two diodes are in series. The first diode has a voltage of 0.75 V and the second has a voltage of 0.8 V. If the current through the first diode is 400 mA, then the current through the second diode is _____ mA.

Answer 1

The current in the second diode is 400mA

Data;

• First Voltage = 0.75V
• Second Voltage = 0.8V
• First Current (I) = 400mA
• Second Current(I) = ?

Current In a Series

The current in the first diode is equal to 400mA. In a series circuit, the current passing the diodes are equal. This implies that the current in the series are equal.

Diodes connected in series will be the equal.

$I_1 = I_2$

Since I1 is 400mA, I2 will be equal to 400mA

$I_1 = I_2\\I_1 = 400mA\\I_2 = 400mA$

The current in the second diode is 400mA

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